About Common & Natural Logarithms:
We can use the change of base rule to change the base of a logarithm into one that is more convenient to work with. We can use this method to obtain a common logarithm or natural logarithm. These two types of logarithms appear on most calculators and can be used to obtain a decimal approximation.
Test Objectives
- Demonstrate the ability to approximate the value of a common logarithm
- Demonstrate the ability to approximate the value of a natural logarithm
- Demonstrate the ability to use the change of base rule to generate a common or natural logarithm
#1:
Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.
a) $$\log_{7}(1.17)$$
b) $$\log_{3}(3.7)$$
c) $$\log_{5}(25)$$
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#2:
Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.
a) $$\log_{6}(70)$$
b) $$\log_{6}(21)$$
c) $$\log_{12}(\sqrt[4]{12})$$
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#3:
Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.
a) $$\log_{3}(81)$$
b) $$\log_{7}(27)$$
c) $$\log_{2}(26)$$
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#4:
Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.
a) $$\log_{5}(33)$$
b) $$\log_{3}(3)$$
c) $$\log_{5}(2)$$
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#5:
Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.
a) $$\log_{5}(-22)$$
b) $$\log_{2}(29)$$
c) $$\log_{6}(\sqrt[8]{6})$$
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Written Solutions:
#1:
Solutions:
a) $$log_{7}(1.17)=\frac{log(1.17)}{log(7)}\approx .081$$
b) $$log_{3}(3.7)=\frac{log(3.7)}{log(3)}\approx 1.191$$
c) $$log_{5}(25)=\frac{log(25)}{log(5)}=2$$
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#2:
Solutions:
a) $$log_{6}(70)=\frac{log(70)}{log(6)}\approx 2.371$$
b) $$log_{6}(21)=\frac{log(21)}{log(6)}\approx 1.699$$
c) $$log_{12}(\sqrt[4]{12})=log_{12}(12^{\frac{1}{4}})=\frac{1}{4}$$
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#3:
Solutions:
a) $$log_{3}(81)=\frac{log(81)}{log(3)}=4$$
b) $$log_{7}(27)=\frac{log(27)}{log(7)}\approx 1.694$$
c) $$log_{2}(26)=\frac{log(26)}{log(2)}\approx 4.7$$
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#4:
Solutions:
a) $$log_{5}(33)=\frac{ln(33)}{ln(5)}\approx 2.173$$
b) $$log_{3}(3)=\frac{log(3)}{log(3)}=1$$
c) $$log_{5}(2)=\frac{ln(2)}{ln(5)}\approx .431$$
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#5:
Solutions:
a) $$undefined$$
b) $$log_{2}(29)=\frac{ln(29)}{ln(2)}\approx 4.858$$
c) $$log_{6}(\sqrt[8]{6})=log_{6}(6^\frac{1}{8})=\frac{1}{8}$$