- Demonstrate an understanding of how to solve a linear system in two variables
- Demonstrate an understanding of how to solve a linear system in three variables
- Learn the six-step method used to solve a word problem with linear systems

## How to Solve Word Problems with Linear Systems

### Applications of Linear Systems

- Read the problem and determine the main objective
- Assign a variable to represent each unknown
- For each variable, we need an equation

- Write a system of linear equations
- Solve the system
- State the answer
- Check the result
- Read back through the problem and determine if the answer is reasonable

Example 1: Solve each word problem.

Jen and Mya are selling snacks for a school fundraiser. Customers can buy packages of figs and packages of cookies. Jen sold 12 packages of figs and 5 packages of cookies for a total of $287. Mya sold 1 package of figs and 10 packages of cookies for a total of $206. Find the sale price for one package of figs and one package of cookies.

Step 1) Read the problem and determine the main objective.

Our goal is to determine the sale price for each package of figs and cookies.

Step 2) Assign a variable to represent each unknown.

Let x = the price in dollars for one package of figs

Then y = the price in dollars for one package of cookies

Step 3) Write a system of linear equations.

While it isn't necessary, it is often useful to organize our information using a table.

Figs | Cookies | Sales | |
---|---|---|---|

Jen | 12 | 5 | 287 |

Mya | 1 | 10 | 206 |

12x + 5y = 287

1x + 10y = 206

The first equation comes from Jen's sales activity. She sells 12 packages of figs, which are x dollars each. She also sells 5 packages of cookies which are y dollars each. If we sum the sales from figs (12x) and the sales from cookies (5y), we get her total sales of 287.

The second equation is set up in the exact same way. We look at Mya's sales activity and find that she sells 1 package of figs for x dollars each. She also sells 10 packages of cookies which are y dollars each. If we sum the sales from figs (1x) and the sales from cookies (10y), we get her total sales of 206.

Step 4) Solve the system.

Let's begin by labeling our equations as 1 and 2.

1) 12x + 5y = 287

2) 1x + 10y = 206

Since equation 2 has a variable with a coefficient of 1, the substitution method would likely be easiest. Let's solve equation 2 for x:

2) x = -10y + 206

Now we can plug in for x in equation 1:

12(-10y + 206) + 5y = 287

-120y + 2472 + 5y = 287

-115y = -2185

y = 19

Let's plug in a 19 for y in equation 2:

2) x + 10y = 206

x + 10(19) = 206

x + 190 = 206

x = 16

Step 5) State the answer.

Since x represents the price of each package of figs and y represents the price of each package of cookies, we know that a package of figs sells for $16 and a package of cookies sells for $19.

Let's write this as a nice clean sentence.

The price of a package of figs is $16 and the price of a package of cookies is $19.

Step 6) Check the result.

To check our result, we read back through our problem. We see that Jen sold 12 packages of figs and 5 packages of cookies for $287.

12(16) + 5(19) = 287

192 + 95 = 287

287 = 287 ✔

Additionally, we see that Mya sold 1 package of figs and 10 packages of cookies for $206.

1(16) + 10(19) = 206

16 + 190 = 206

206 = 206 ✔

Example 2: Solve each word problem.

A passenger jet traveled 1100 miles each way to Canada and back. The trip there was with the wind and took 10 hours. The trip back was into the wind and took 22 hours. What is the speed of the plane in still air? What is the speed of the wind?

Step 1) Read the problem and determine the main objective.

Our goal is to determine the speed of the plane in still air and the speed of the wind.

Step 2) Assign a variable to represent each unknown.

Let x = speed of the plane in still air

Then y = speed of the wind

Step 3) Write a system of linear equations.

Again, let's use a table to organize our information. Remember with a motion word problem, we use the distance formula:

d = r • t

Distance | Rate | Time | |
---|---|---|---|

There | 1100 | x + y | 10 |

Back | 1100 | x - y | 22 |

10(x + y) = 1100

22(x - y) = 1100

The first equation represents the trip there. We are following the formula: d = r • t. For the distance, we are given a value of 1100 miles for each scenario. Since the trip there involves traveling "with" the wind, our rate is the speed of the wind (y) plus the speed of the plane in still air (x). The time traveled is given to us as 10 hours. We put our equation together as the rate: (x + y), multiplied by the time 10, which is set equal to the distance of 1100.

The second equation represents the trip back. We are following the formula: d = r • t. For the distance, we are given a value of 1100 miles for each scenario. Since the trip back involves traveling "against" the wind, our rate is the speed of the plane in still air (x) minus the speed of the wind (y). The time traveled is given to us as 22 hours. We put our equation together as the rate: (x - y), multiplied by the time 22, which is set equal to the distance of 1100.

Step 4) Solve the system.

Let's begin by labeling our equations as 1 and 2.

1) 10(x + y) = 1100

2) 22(x - y) = 1100

For equation 1, let's divide each side by 10:

1) x + y = 110

For equation 2, let's divide each side by 22:

2) x - y = 50

Since we have +1y and -1y, it is easier to use elimination. $$\require{cancel}x + \cancel{y}=110$$ $$\underline{x + \cancel{-y}=50}$$ $$2x=160$$ $$x=80$$ We can plug an 80 in for x in either equation 1 or 2. Let's use equation 1:

10(x + y) = 1100

10(80 + y) = 1100

80 + y = 110

y = 30

Step 5) State the answer.

Since x represents the speed of the plane in still air, and y represents the wind speed, we know the plane traveled at an average speed of 80 miles per hour in still air and the average wind speed was 30 miles per hour.

Let's write this as a nice clean sentence.

The speed of the plane was 80 miles per hour, while the wind speed was 30 miles per hour.

Step 6) Check the result.

To check our result, we read back through our problem. We see that on the trip there, the plane traveled at an average speed of 110 miles per hour. This accounts for the wind speed plus the plane speed in still air. If we multiply this by the time traveled of 10 hours, we do get a distance of 1100 miles.

10(80 + 30) = 1100

10(110) = 1100

1100 = 1100 ✔

Additionally, we see that on the trip back, the plane traveled at an average speed of 50 miles per hour. This accounts for the speed of the plane in still air minus the wind speed. If we multiply this by the time traveled of 22 hours, we do get a distance of 1100 miles.

22(80 - 30) = 1100

22(50) = 1100

1100 = 1100 ✔

Example 3: Solve each word problem.

Nobot Robotics Company produces three toy robots, models Dot, Lea, and Liz. To manufacture each toy robot, the company must use labor hours for coding, assembly, and painting. The amounts for each robot are shown in the table below:

Dot | Lea | Liz | |
---|---|---|---|

Coding | 4 | 5 | 1 |

Assembly | 7 | 9 | 2 |

Painting | 4 | 2 | 1 |

Step 1) Read the problem and determine the main objective.

Our goal is to determine how many of each type of toy robot is being produced on a daily basis.

Step 2) Assign a variable to represent each unknown.

Let x = number of Dot models produced in a day

Then y = number of Lea models produced in a day

Then z = number of Liz models produced in a day

Step 3) Write a system of linear equations.

Again, let's use a table to organize our information. We will take the above table and add in the total daily hours given for coding, assembly, and painting.

Dot | Lea | Liz | Totals | |
---|---|---|---|---|

Coding | 4 | 5 | 1 | 165 |

Assembly | 7 | 9 | 2 | 295 |

Painting | 4 | 2 | 1 | 150 |

4x + 5y + z = 165

7x + 9y + 2z = 295

4x + 2y + z = 150

For the first equation, we think about the hours allotted for coding. Each model Dot requires 4 hours for coding, where Lea requires 5, and Liz requires 1. Since we have 165 hours available for coding, we can multiply the number of hours it takes to code each model by the number of models produced. If we sum these amounts for the three models, it will be equal to the total amount of hours spent on coding, which is 165.

Similarly, for the second equation, we think about the hours allotted for assembly. Each Dot requires 7 hours for assembly, where Lea requires 9, and Liz requires 2. Since we have 295 hours available for assembly, we can multiply the number of hours it takes to assemble each model by the number of models produced. If we sum these amounts for the three models, it will be equal to the total amount of hours spent on code, which is 295.

Lastly, for the third equation, we think about the hours allotted for painting. Each Dot requires 4 hours for painting, where Lea requires 2, and Liz requires 1. Since we have 150 hours available for painting, we can multiply the number of hours it takes to paint each model by the number of models produced. If we sum these amounts for the three models, it will be equal to the total amount of hours spent on painting, which is 150.

Step 4) Solve the system.

Let's begin by labeling our equations as 1, 2, and 3.

1) 4x + 5y + z = 165

2) 7x + 9y + 2z = 295

3) 4x + 2y + z = 150

It seems easiest to eliminate the variable z. Let's multiply equation 1 by (-1) and add this result to equation 3:

1) -4x - 5y - z = -165

3) 4x + 2y + z = 150 $$\cancel{-4x}- 5y + \cancel{-z}-165$$ $$\underline{\cancel{4x}+ 2y + \cancel{z}=150}$$ $$-3y=-15$$ $$y=5$$ Let's eliminate z from equations 2 and 3. We can multiply equation 3 by (-2) and add the result to equation 2:

3) -8x - 4y - 2z = -300

2) 7x + 9y + 2z = 295

$$-8x - 4y + \cancel{-2z}=-300$$ $$\underline{7x + 9y + \cancel{2z}=295}$$ $$-x + 5y=-5$$ Since we already know that y is 5, let's plug this in and find the value for x:

-x + 5y = -5

-x + 5(5) = -5

-x + 25 = -5

-x = -30

x = 30

At this point, we know that x is 30 and y is 5. Let's plug into equation 1 and find the value for z:

1) 4x + 5y + z = 165

4(30) + 5(5) + z = 165

120 + 25 + z = 165

145 + z = 165

z = 20

Step 5) State the answer.

Since x represents the number of Dot models produced in a day, y represents the number of Lea models produced in a day, and z represents the number of Liz models produced in a day, we can state our answer as:

On a daily basis, Nobot produces 30 Dot model robots, along with 5 Lea Robots, and 20 Liz Robots.

Step 6) Check the result.

Coding:

4(30) + 5(5) + 1(20) = 165

120 + 25 + 20 = 165

165 = 165 ✔

Assembly:

7(30) + 9(5) + 2(20) = 295

210 + 45 + 40 = 295

295 = 295 ✔

Painting:

4(30) + 2(5) + 1(20) = 150

120 + 10 + 20 = 150

150 = 150 ✔

#### Skills Check:

Example #1

Solve each word problem.

The senior classes at Willow Creek High School and Highland High School planned separate trips to Honey Island Swamp. The senior class at Willow Creek High School rented and filled 64 vans and 64 buses with 4096 students. Highland High School rented and filled 12 vans and 42 buses with 2448 students. Each van contained the same number of students. Additionally, each bus contained the same number of students. Find the number of students in each van (V) and in each bus (B).

Please choose the best answer.

Example #2

Solve each word problem.

Megan and Julia each improved their yards by planting grass sod and Begonias. They bought their supplies from the same gardening store. Megan spent $236 on 82 square feet of grass sod and 18 Begonias. Julia spent $432 on 62 square feet of grass sod and 77 Begonias. Find the cost of one square foot of grass sod (G) and the cost of one Begonia (B).

Please choose the best answer.

Example #3

Solve each word problem.

Becky won $90,000 in a local lottery and decided to invest in a money market account, municipal bonds, and a certificate of deposit (CD). The money market account pays 2% annual simple interest, while the municipal bonds pay 5% annual simple interest, and the CD pays 3.5% annual simple interest. After one year, Becky received a total of $3000 in simple interest from the three investments. If there was half as much invested in the CD as the money market account, how much was invested in the municipal bonds?

Please choose the best answer.

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