### About Common & Natural Logarithms:

We can use the change of base rule to change the base of a logarithm into one that is more convenient to work with. We can use this method to obtain a common logarithm or natural logarithm. These two types of logarithms appear on most calculators and can be used to obtain a decimal approximation.

Test Objectives
• Demonstrate the ability to approximate the value of a common logarithm
• Demonstrate the ability to approximate the value of a natural logarithm
• Demonstrate the ability to use the change of base rule to generate a common or natural logarithm
Common & Natural Logarithms Practice Test:

#1:

Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.

a) $$\log_{7}(1.17)$$

b) $$\log_{3}(3.7)$$

c) $$\log_{5}(25)$$

#2:

Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.

a) $$\log_{6}(70)$$

b) $$\log_{6}(21)$$

c) $$\log_{12}(\sqrt{12})$$

#3:

Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.

a) $$\log_{3}(81)$$

b) $$\log_{7}(27)$$

c) $$\log_{2}(26)$$

#4:

Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.

a) $$\log_{5}(33)$$

b) $$\log_{3}(3)$$

c) $$\log_{5}(2)$$

#5:

Instructions: Use the change of base rule and a calculator to approximate each to 3 decimal places.

a) $$\log_{5}(-22)$$

b) $$\log_{2}(29)$$

c) $$\log_{6}(\sqrt{6})$$

Written Solutions:

#1:

Solutions:

a) $$log_{7}(1.17)=\frac{log(1.17)}{log(7)}\approx .081$$

b) $$log_{3}(3.7)=\frac{log(3.7)}{log(3)}\approx 1.191$$

c) $$log_{5}(25)=\frac{log(25)}{log(5)}=2$$

#2:

Solutions:

a) $$log_{6}(70)=\frac{log(70)}{log(6)}\approx 2.371$$

b) $$log_{6}(21)=\frac{log(21)}{log(6)}\approx 1.699$$

c) $$log_{12}(\sqrt{12})=log_{12}(12^{\frac{1}{4}})=\frac{1}{4}$$

#3:

Solutions:

a) $$log_{3}(81)=\frac{log(81)}{log(3)}=4$$

b) $$log_{7}(27)=\frac{log(27)}{log(7)}\approx 1.694$$

c) $$log_{2}(26)=\frac{log(26)}{log(2)}\approx 4.7$$

#4:

Solutions:

a) $$log_{5}(33)=\frac{ln(33)}{ln(5)}\approx 2.173$$

b) $$log_{3}(3)=\frac{log(3)}{log(3)}=1$$

c) $$log_{5}(2)=\frac{ln(2)}{ln(5)}\approx .431$$

#5:

Solutions:

a) $$undefined$$

b) $$log_{2}(29)=\frac{ln(29)}{ln(2)}\approx 4.858$$

c) $$log_{6}(\sqrt{6})=log_{6}(6^\frac{1}{8})=\frac{1}{8}$$