Question 1 of 5: Determine if each is a solution to the equation
A
$$x=1(n),x=5(y),x=7(n)$$ $$x=1(n)$$$$x=5(y)$$$$x=7(n)$$
B
$$x=1(y),x=5(y),x=7(n)$$ $$x=1(y)$$$$x=5(y)$$$$x=7(n)$$
C
$$x=1(n),x=5(y),x=7(y)$$ $$x=1(n)$$$$x=5(y)$$$$x=7(y)$$
D
$$x=1(y),x=5(n),x=7(n)$$ $$x=1(y)$$$$x=5(n)$$$$x=7(n)$$
E
$$x=1(y),x=5(y),x=7(y)$$ $$x=1(y)$$$$x=5(y)$$$$x=7(y)$$
Question 2 of 5: Determine if each is a solution to the equation
A
$$x=-4(y),x=9(y),x=11(n)$$ $$x=-4(y)$$$$x=9(y)$$$$x=11(n)$$
B
$$x=-4(y),x=9(n),x=11(n)$$ $$x=-4(y)$$$$x=9(n)$$$$x=11(n)$$
C
$$x=-4(n),x=9(y),x=11(y)$$ $$x=-4(n)$$$$x=9(y)$$$$x=11(y)$$
D
$$x=-4(n),x=9(y),x=11(n)$$ $$x=-4(n)$$$$x=9(y)$$$$x=11(n)$$
E
$$x=-4(n),x=9(n),x=11(n)$$ $$x=-4(n)$$$$x=9(n)$$$$x=11(n)$$
Question 3 of 5: Determine if each is a solution to the equation
A
$$x=-2(n),x=6(n),x=14(n)$$ $$x=-2(n)$$$$x=6(n)$$$$x=14(n)$$
B
$$x=-2(y),x=6(n),x=14(n)$$ $$x=-2(y)$$$$x=6(n)$$$$x=14(n)$$
C
$$x=-2(n),x=6(y),x=14(y)$$ $$x=-2(n)$$$$x=6(y)$$$$x=14(y)$$
D
$$x=-2(y),x=6(n),x=14(y)$$ $$x=-2(y)$$$$x=6(n)$$$$x=14(y)$$
E
$$x=-2(n),x=6(n),x=14(y)$$ $$x=-2(n)$$$$x=6(n)$$$$x=14(y)$$
Question 4 of 5: Determine if each is a solution to the equation
A
$$\frac{9}{23}(n),\frac{5}{12}(n),\frac{19}{11}(y)$$ $$\frac{9}{23}(n)$$$$\frac{5}{12}(n)$$$$\frac{19}{11}(y)$$
B
$$\frac{9}{23}(y),\frac{5}{12}(n),\frac{19}{11}(n)$$ $$\frac{9}{23}(y)$$$$\frac{5}{12}(n)$$$$\frac{19}{11}(n)$$
C
$$\frac{9}{23}(n),\frac{5}{12}(y),\frac{19}{11}(n)$$ $$\frac{9}{23}(n)$$$$\frac{5}{12}(y)$$$$\frac{19}{11}(n)$$
D
$$\frac{9}{23}(n),\frac{5}{12}(n),\frac{19}{11}(n)$$ $$\frac{9}{23}(n)$$$$\frac{5}{12}(n)$$$$\frac{19}{11}(n)$$
E
$$\frac{9}{23}(y),\frac{5}{12}(y),\frac{19}{11}(y)$$ $$\frac{9}{23}(y)$$$$\frac{5}{12}(y)$$$$\frac{19}{11}(y)$$
Question 5 of 5: Determine if each is a solution to the equation
A
$$x=3.5(n),x=9.3(n),x=12.45(n)$$ $$x=3.5(n)$$$$x=9.3(n)$$$$x=12.45(n)$$
B
$$x=3.5(y),x=9.3(n),x=12.45(n)$$ $$x=3.5(y)$$$$x=9.3(n)$$$$x=12.45(n)$$
C
$$x=3.5(n),x=9.3(y),x=12.45(n)$$ $$x=3.5(n)$$$$x=9.3(y)$$$$x=12.45(n)$$
D
$$x=3.5(n),x=9.3(n),x=12.45(y)$$ $$x=3.5(n)$$$$x=9.3(n)$$$$x=12.45(y)$$
E
$$x=3.5(y),x=9.3(y),x=12.45(y)$$ $$x=3.5(y)$$$$x=9.3(y)$$$$x=12.45(y)$$