Solving Equations with Rational Expressions Test

Question 1 of 5: Solve each Equation

$$\frac{3x+1}{x-4}=\frac{6x+5}{2x-7}$$

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No Solution

$$x=5,-3$$

$$x=-\frac{7}{3}$$

$$x=\frac{7}{3},-\frac{1}{5}$$

$$x=-4$$

Question 2 of 5: Solve each Equation

$$\frac{x-4}{x+6}=\frac{2x+3}{2x-1}$$

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$$x=-12,7$$

No Solution

$$x=\frac{5}{12}$$

$$x=-2$$

$$x=-\frac{7}{12}$$

Question 3 of 5: Solve each Equation

$$\frac{1}{x^2+2x}=\frac{1}{x}+\frac{14x+14}{x+2}$$ $$\frac{1}{x^2+2x}=$$$$\frac{1}{x}+\frac{14x+14}{x+2}$$

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$$x=5,-12$$

$$x=-\frac{2}{7}$$

No Solution

$$x=-1,-\frac{1}{14}$$

$$x=-\frac{1}{14}$$

Question 4 of 5: Solve each Equation

$$\frac{x^2-28x+196}{x^2+14x+48}=\frac{x-4}{x+8}+\frac{10}{x+8}$$ $$\frac{x^2-28x+196}{x^2+14x+48}=$$$$\frac{x-4}{x+8}+\frac{10}{x+8}$$

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$$x=\frac{1}{4},-2$$

$$x=-1,7$$

$$x=-\frac{4}{7},-4$$

No Solution

$$x=4$$

Question 5 of 5: Solve each Equation

$$\frac{x^2-8x-33}{x^2+4x}=\frac{1}{x}+\frac{x+2}{x}$$ $$\frac{x^2-8x-33}{x^2+4x}=$$$$\frac{1}{x}+\frac{x+2}{x}$$

Finish »

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$$-\frac{5}{3},7$$

$$x=-5,3$$

No Solution

$$x=-\frac{2}{3},-3$$

$$x=-3$$

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