Question 1 of 5Translate each into an Equation and Solve
Select the Correct Answer Below: Correct! Not Correct!
A
$$5(3x-90)=6,x=30$$ $$5(3x-90)=6,x=30$$ $$5(3x-90)=6$$$$x=30$$
B
$$-90-6x=5x,x=-\frac{90}{11}$$ $$-90-6x=5x,x=-\frac{90}{11}$$ $$-90-6x=5x$$$$x=-\frac{90}{11}$$
C
$$5(6-3x)=-90,x=8$$ $$5(6-3x)=-90,x=8$$ $$5(6-3x)=-90$$$$x=8$$
D
$$3(5-90x)=6,x=\frac{1}{30}$$ $$3(5-90x)=6,x=\frac{1}{30}$$ $$3(5-90x)=6$$$$x=\frac{1}{30}$$
E
$$5(3x-6)=-90x,x=\frac{2}{7}$$ $$5(3x-6)=-90x,x=\frac{2}{7}$$ $$5(3x-6)=-90x$$$$x=\frac{2}{7}$$
Question 2 of 5Translate each into an Equation and Solve
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A
$$-8-6(8x+1)=130, x=-3$$ $$-8-6(8x+1)=130$$$$x=-3$$ $$-8-6(8x+1)$$$$=130$$$$x=-3$$
B
$$6(-8x+1)=130, x=-\frac{31}{12}$$ $$6(-8x+1)=130$$$$x=-\frac{31}{12}$$ $$6(-8x+1)=130$$$$x=-\frac{31}{12}$$
C
$$6x-8=130,x=23$$ $$6x-8=130$$$$x=23$$ $$6x-8=130$$$$x=23$$
D
$$-1(8x-6)=130, x=-\frac{31}{2}$$ $$-1(8x-6)=130$$$$x=-\frac{31}{2}$$ $$-1(8x-6)=130$$$$x=-\frac{31}{2}$$
E
$$-8-6(130x+1)=8, x=-11$$ $$-8-6(130x+1)=8$$$$x=-11$$ $$-8-6(130x+1)$$$$=8$$$$x=-11$$
Question 3 of 5Translate each into an Equation and Solve
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A
$$-1-7x=6-8x,x=7$$ $$-1-7x=6-8x,x=7$$ $$-1-7x=6-8x$$$$x=7$$
B
$$-7x-1=8x-6,x=\frac{1}{3}$$ $$-7x-1=8x-6,x=\frac{1}{3}$$ $$-7x-1=8x-6$$$$x=\frac{1}{3}$$
C
$$6x-1=-1-8x,x=0$$ $$6x-1=-1-8x,x=0$$ $$6x-1=-1-8x$$$$x=0$$
D
$$-x+7=x-6(8-x), x=\frac{55}{8}$$ $$-x+7=x-6(8-x)$$$$x=\frac{55}{8}$$ $$-x+7=$$$$x-6(8-x)$$$$x=\frac{55}{8}$$
E
$$-6x-1=8-x, x=-\frac{9}{5}$$ $$-6x-1=8-x, x=-\frac{9}{5}$$ $$-6x-1=8-x$$$$x=-\frac{9}{5}$$
Question 4 of 5Translate each into an Equation and Solve
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A
$$4(9x+1)+(x+5)=7, x=-\frac{2}{37}$$ $$4(9x+1)+(x+5)=7$$$$x=-\frac{2}{37}$$ $$4(9x+1)\hspace{.25em}+$$$$(x+5)=7$$$$x=-\frac{2}{37}$$
B
$$4x+7(x+1)+9=5, x=-1$$ $$4x+7(x+1)+9=5$$$$x=-1$$ $$4x+7(x+1)$$$$+\hspace{.25em}9=5$$$$x=-1$$
C
$$9x+7(x+1)=5, x=-\frac{1}{8}$$ $$9x+7(x+1)=5$$$$x=-\frac{1}{8}$$ $$9x+7(x+1)=5$$$$x=-\frac{1}{8}$$
D
$$4x+9(x+7)+5=1, x=-13$$ $$4x+9(x+7)+5=1$$$$x=-13$$ $$4x+9(x+7)$$$$+\hspace{.25em}5=1$$$$x=-13$$
E
$$9(4x+1)+7(x+5)=1, x=-1$$ $$9(4x+1)+7(x+5)=1$$$$x=-1$$ $$9(4x+1)$$$$+\hspace{.25em}7(x+5)=1$$$$x=-1$$
Question 5 of 5Translate each into an Equation and Solve
Select the Correct Answer Below: Correct! Not Correct!
A
$$5\frac{x}{4}+\frac{14}{127}=\frac{46}{7}x,x=-5$$ $$5\frac{x}{4}+\frac{14}{127}=\frac{46}{7}x$$$$x=-5$$ $$5\frac{x}{4}+\frac{14}{127}$$$$=\frac{46}{7}x$$$$x=-5$$
B
$$x+\frac{127}{14}=5x+\frac{46}{7},x=-1$$ $$x+\frac{127}{14}=5x+\frac{46}{7}$$$$x=-1$$ $$x+\frac{127}{14}$$$$=5x+\frac{46}{7}$$$$x=-1$$
C
$$\frac{5}{4x}+\frac{127}{14}=\frac{46}{7},x=\frac{13}{17}$$ $$\frac{5}{4x}+\frac{127}{14}=\frac{46}{7}$$$$x=\frac{13}{17}$$ $$\frac{5}{4x}+\frac{127}{14}=\frac{46}{7}$$$$x=\frac{13}{17}$$
D
$$\frac{x+5}{4}+\frac{46}{14}=x+\frac{127}{7},x=-\frac{127}{7}$$ $$\frac{x+5}{4}+\frac{46}{14}=x+\frac{127}{7}$$$$x=-\frac{127}{7}$$ $$\frac{x+5}{4}+\frac{46}{14}$$$$=x+\frac{127}{7}$$$$x=-\frac{127}{7}$$
E
$$\frac{5}{4}x+\frac{127}{14}=x+\frac{46}{7},x=-10$$ $$\frac{5}{4}x+\frac{127}{14}=x+\frac{46}{7}$$$$x=-10$$ $$\frac{5}{4}x+\frac{127}{14}$$$$=x+\frac{46}{7}$$$$x=-10$$

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