Question 1 of 5: Find the inverse:
A
$$f^{-1}(x)=x^2 + 7$$ $$x ≥ 0$$
B
$$f^{-1}(x)=\frac{x^2}{7}$$ $$x ≥ 0$$
C
$$f^{-1}(x)=\frac{x^2}{2}- 7$$ $$x ≥ 0$$
D
$$f^{-1}(x)=\frac{x^2 - 7}{2}$$ $$x ≤ 0$$
E
$$f^{-1}(x)=x^2 + 7$$ $$x ≤ 0$$
Question 2 of 5: Find the inverse:
A
$$f^{-1}(x)=\frac{-x^2 + 3}{2}$$ $$x ≥ 0$$
B
$$f^{-1}(x)=-x^2 + 3$$ $$x ≤ 0$$
C
$$f^{-1}(x)=-x^2 + 3$$ $$x ≥ 0$$
D
$$f^{-1}(x)=\frac{-x^2}{2}+ 3$$ $$x ≤ 0$$
E
$$f^{-1}(x)=\frac{-x^2 + x}{2}$$ $$x ≥ 0$$
Question 3 of 5: Find the inverse:
A
$$f^{-1}(x)=\sqrt{x - 2}+ 3$$
B
$$f^{-1}(x)=-\sqrt{x - 2}+ 3$$
C
$$f^{-1}(x)=\frac{-\sqrt{x + 2}+ 3}{2}$$
D
$$f^{-1}(x)=\frac{-\sqrt{x - 2}+ 3}{2}$$
E
$$f^{-1}(x)=\frac{\sqrt{x + 3}}{2}$$
Question 4 of 5: Find the inverse:
A
$$f^{-1}(x)=\frac{3\sqrt{x}}{x}$$
B
$$f^{-1}(x)=\frac{\sqrt{x}}{3x}$$
C
$$f^{-1}(x)=\frac{\sqrt{x}+ 3x}{x}$$
D
$$f^{-1}(x)=\frac{|x| - 3x}{x - 3}$$
E
$$f^{-1}(x)=\frac{x^3 - 3x}{3x - 1}$$
Question 5 of 5: Find the inverse:
A
$$f^{-1}(x)=\frac{2 \sqrt{1 - 2x}}{1 - 2x}$$
B
$$f^{-1}(x)=\frac{\sqrt{1 - 2x}}{1 - 2x}+ 2$$
C
$$f^{-1}(x)=1 - \sqrt{2x + 1}$$
D
$$f^{-1}(x)=\frac{x^2 - 1}{x}$$
E
$$f^{-1}(x)=\frac{2 \sqrt{2x}}{x + 1}$$