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Question 1 of 5Match the graph to its equation:
graphing ([(x - 3)^2] / [4]) - ([y^2] / [16])=1
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Select the Correct Answer Below: Correct! Cool Emoji Not Correct! Cool Emoji
A
$$\frac{(x - 3)^2}{4}- \frac{(y - 4)^2}{16}=1$$
B
$$\frac{x^2}{4}- \frac{y^2}{16}=1$$
C
$$\frac{(x - 3)^2}{4}- \frac{y^2}{16}=1$$
D
$$\frac{x^2}{4}- \frac{(y - 3)^2}{16}=1$$
E
$$\frac{(x - 1)^2}{16}- \frac{(y - 4)^2}{4}=1$$
Question 2 of 5Write in standard form:
$$\text{vertices:} \, (-2, 9), (-6,9)$$ $$\text{foci:} \,(-4 + 2\sqrt{26}, 9), (-4 - 2\sqrt{26}, 9)$$
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Select the Correct Answer Below: Correct! Cool Emoji Not Correct! Cool Emoji
A
$$\frac{(y + 4)^2}{100}- \frac{(x + 9)^2}{4}=1$$
B
$$\frac{(y - 9)^2}{25}- \frac{(x + 4)^2}{4}=1$$
C
$$\frac{(x + 4)^2}{100}- \frac{(y - 9)^2}{25}=1$$
D
$$\frac{(x - 10)^2}{25}- \frac{(y + 4)^2}{16}=1$$
E
$$\frac{(x + 4)^2}{4}- \frac{(y - 9)^2}{100}=1$$
Question 3 of 5Write in standard form:
$$\text{vertices:} \, (-8, 12), (-8,2)$$ $$\text{asymptotes:}$$ $$y = \frac{5}{11}x + \frac{117}{11}$$ $$y = -\frac{5}{11}x + \frac{37}{11}$$
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Select the Correct Answer Below: Correct! Cool Emoji Not Correct! Cool Emoji
A
$$\frac{(y - 7)^2}{25}- \frac{(x + 8)^2}{121}=1$$
B
$$\frac{(y - 9)^2}{100}- \frac{(x + 17)^2}{25}=1$$
C
$$\frac{(x + 12)^2}{81}- \frac{(y + 25)^2}{19}=1$$
D
$$\frac{(y - 9)^2}{10}- \frac{(x - 21)^2}{5}=1$$
E
$$\frac{(y + 8)^2}{64}- \frac{(x + 9)^2}{81}=1$$
Question 4 of 5Write in standard form:
$$-x^2 + y^2 + 10x - 6y - 81=0$$
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Select the Correct Answer Below: Correct! Cool Emoji Not Correct! Cool Emoji
A
$$\frac{(x + 5)^2}{65}- \frac{(y + 3)^2}{65}=1$$
B
$$\frac{(y + 5)^2}{65}- \frac{(x + 3)^2}{65}=1$$
C
$$\frac{(x - 7)^2}{13}- \frac{(y - 5)^2}{10}=1$$
D
$$\frac{(y - 3)^2}{65}- \frac{(x - 5)^2}{65}=1$$
E
$$\frac{(x - 10)^2}{11}- \frac{(y - 11)^2}{11}=1$$
Question 5 of 5Write in standard form:
$$4x^2 - 5y^2 + 48x - 56=0$$
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Select the Correct Answer Below: Correct! Cool Emoji Not Correct! Cool Emoji
A
$$\frac{y^2}{40}- \frac{(x + 6)^2}{50}=1$$
B
$$\frac{(x + 6)^2}{50}- \frac{y^2}{40}=1$$
C
$$\frac{(y - 5)^2}{20}- \frac{(x - 6)^2}{50}=1$$
D
$$\frac{(x - 6)^2}{50}- \frac{y^2}{4}=1$$
E
$$(x + 6)^2 - \frac{y^2}{16}=1$$

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